A Kenyan political group is protesting US President Barack Obama’s visit by asking 5,000 men and women to go naked.
The Republican Liberty Party, a far-right anti-abortion, anti-homosexuality group, have sought permission to hold the ‘peaceful protest’ on 22 and 23 July.
Leader Vincent Kidala sent a letter to the county commander yesterday (13 July), with the intention to show Obama and the Kenyan people the ‘differences’ between the sexes.
‘The procession shall be carried out by approximately 5,000 totally naked men and women to protest over Obama’s open and aggressive support for homosexuality,’ he said in the letter.
‘The party’s main objective is for him to see and understand the different [sic] between a man and a woman’.
Kidala has confirmed the veracity of the letter, telling local media the party will get in touch with a ‘network of prostitutes’ in order to reach the expected goal of 5,000 people.
He has claimed the prostitutes have agreed to participate free of charge as they will ‘lose customers’ if homosexuality is legalized.
Denis Nzioka, a LGBTI rights activist in Kenya, has described the protest as the ‘height of stupidity’.
‘This is a kneejerk reaction after only 25 showed up at their last homophobic rally,’ he told Gay Star News. ‘I’m trying to figure out how exactly they figure 5,000 people will show up with no clothes on to protest Obama and gay rights.
‘This time, not even 25 people will show up.’
He added: ‘They want to show to the people and to Obama the “differences” between men and women, that a penis enters a vagina. That’s how they think, and that’s how stupid and ridiculous and ignorant this is. The Republican Liberty Party just trying to stay relevant.’
Kenyan lawmakers have attempted to put a gag order on Obama in order to stop him from mentioning LGBTI rights while he is in the country later this month.
However State House has ignored this call, allowing the US president to speak freely.
Same-sex activity is illegal in Kenya, punishable by up to 14 years in prison.